5x+4/2x+6(x^2+7x+12)

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Solution for 5x+4/2x+6(x^2+7x+12) equation:


x in (-oo:+oo)

6*(x^2+7*x+12)+5*x+(4/2)*x = 0

6*(x^2+7*x+12)+5*x+2*x = 0

6*(x^2+7*x+12)+5*x+2*x = 0

6*x^2+47*x+2*x+72 = 0

6*x^2+49*x+72 = 0

6*x^2+49*x+72 = 0

6*x^2+49*x+72 = 0

DELTA = 49^2-(4*6*72)

DELTA = 673

DELTA > 0

x = (673^(1/2)-49)/(2*6) or x = (-673^(1/2)-49)/(2*6)

x = (673^(1/2)-49)/12 or x = (-(673^(1/2)+49))/12

(x+(673^(1/2)+49)/12)*(x-((673^(1/2)-49)/12)) = 0

(x+(673^(1/2)+49)/12)*(x-((673^(1/2)-49)/12)) = 0

( x+(673^(1/2)+49)/12 )

x+(673^(1/2)+49)/12 = 0 // - (673^(1/2)+49)/12

x = -((673^(1/2)+49)/12)

( x-((673^(1/2)-49)/12) )

x-((673^(1/2)-49)/12) = 0 // + (673^(1/2)-49)/12

x = (673^(1/2)-49)/12

x in { -((673^(1/2)+49)/12), (673^(1/2)-49)/12 }

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